One kWh is equal to
a) $860\;kcal$
b) $800\;kcal$
c) $746\;kcal$
d) $736\;kcal$
Correct Answer: Option A
Solution:
One kWh = $860.4\;kcal$
One calorie or kcal = $4184\;J$ or $4.18\;kJ$
Showing posts with label Kerala Polytechnic lecturer 2016 - E&I. Show all posts
Showing posts with label Kerala Polytechnic lecturer 2016 - E&I. Show all posts
07 August 2022
Circuit Theory
One kWh = $860.4\;kcal$
Circuit Theory
One kWh is equal to
a) $860\;kcal$
b) $800\;kcal$
c) $746\;kcal$
d) $736\;kcal$
Correct Answer: Option A
Solution:
One kWh = $860.4\;kcal$
One calorie or kcal = $4184\;J$ or $4.18\;kJ$
Circuit Theory
A $100\;W$ bulb, a $40\;W$ fluorescent lamp and a $60\;W$ fan in a room operates for an average duration of $5$ hours in a day. What will be the total energy consumed during the month of April $2016$?
a) $3\;kWh$
b) $30\;kWh$
c) $300\;kWh$
d) $3000 \;kWh$
Correct Answer: Option B
Solution:
Total power = $100+40+60\;W$ $=200\;W$
Since Energy = Power $×$ time period
Power = $200\;W$
Time period = $5$ hours in $30$ days (April $2016$)
$$E=200×5×30\;Wh$$ $$E=30,000\;Wh$$ $$E=30\;kWh$$
Circuit Theory
A $100\;W$ bulb, a $40\;W$ fluorescent lamp and a $60\;W$ fan in a room operates for an average duration of $5$ hours in a day. What will be the total energy consumed during the month of April $2016$?
a) $3\;kWh$
b) $30\;kWh$
c) $300\;kWh$
d) $3000 \;kWh$
Correct Answer: Option B
Solution:
Total power = $100+40+60\;W$ $=200\;W$
Since Energy = Power $×$ time period
Power = $200\;W$
Time period = $5$ hours in $30$ days (April $2016$)
$$E=200×5×30\;Wh$$ $$E=30,000\;Wh$$ $$E=30\;kWh$$
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